**Contents**show

## What is the probability of rolling a 9 with a pair of dice?

Probabilities for the two dice

Total | Number of combinations | Probability |
---|---|---|

6 | 5 | 13.89% |

7 | 6 | 16.67% |

8 | 5 | 13.89% |

9 | 4 |
11.11% |

## What is the probability that the sum of the numbers on your dice is exactly 9?

There are 6*6 possible combos from two six sided dice, or 36 possibilities. If one die A is a 4, in order for the sum to be exactly 9, die B has to land on **5**. Alternatively, if die B is the one that lands on 4, then die A has to land on 5. So, there are only 2 combos that sum to 9 and have at least 1 of the die be a 4.

## What is the probability of getting a total of atleast 9 in a single throw of two dice?

= 4 / 36 = **1/9**.

## What is the ratio of rolling a 2 to rolling a 5?

Two (6-sided) dice roll probability table

Roll a… | Probability |
---|---|

2 | 1/36 (2.778%) |

3 | 2/36 (5.556%) |

4 | 3/36 (8.333%) |

5 | 4/36 (11.111%) |

## What is the probability of rolling an odd number?

The probability when rolling a regular six-sided dice that the score is an odd number is **three-sixths or three out of six**.

## What is the probability of obtaining a sum of nine?

The probability of getting 9 as the sum when 2 dice are thrown is **1/9**.

## What is the probability of getting a prime number from 1 to 100?

The prime numbers from 1 to 100 are: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97. Hence, the probability of the event that a number chosen from 1 to 100 is a prime number . Therefore, the correct option is (C).

## How many outcomes have a sum of at least 9?

(ii) two numbers appearing on them whose sum is 9. Therefore, total number of possible outcomes = **36**.

## What is the formula of probability?

P(**A**) is the probability of an event “A” n(A) is the number of favourable outcomes. n(S) is the total number of events in the sample space.

…

Basic Probability Formulas.

All Probability Formulas List in Maths | |
---|---|

Conditional Probability | P(A | B) = P(A∩B) / P(B) |

Bayes Formula | P(A | B) = P(B | A) ⋅ P(A) / P(B) |

## What is the probability of getting 1 and 5 If a dice is thrown once?

So they are mutually exclusive events, therefore their probabilities add to 1. By symmetry we expect that each face is equally likely to appear and so each has probability = **1/6**. The outcome of a 5 is one of those events and so has probability = 1/6 of appearing.

## Which is more likely rolling a total of 9 when two dice are rolled or rolling a total of 9 when 3 dice are rolled?

Which is more likely, rolling a total of 9 when two dice are rolled or rolling a total of 9 when three dice are rolled? Answer: 9 = 3+6 = 4+5 = 5+4 = 6+3, — 4 ways to get total of 9 points rolling two dice, so the probability that the outcome is 9 points is: 4/(6*6) = 1/9 = **0.111**.