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## What’s the sample space for rolling two dice?

Since there are six rows, there are six possible outcomes where the sum of the two dice is equal to seven. The number of total possible outcomes remains 36. Again, we find the probability by dividing the event frequency (6) by the size of the sample space (36), resulting in a probability of **1/6**.

## What is the probability of rolling 2 dice?

Two (6-sided) dice roll probability table

Roll a… | Probability |
---|---|

2 |
1/36 (2.778%) |

3 | 2/36 (5.556%) |

4 | 3/36 (8.333%) |

5 | 4/36 (11.111%) |

## What are the odds of rolling a 6 with 2 dice?

Probabilities for the two dice

Total | Number of combinations | Probability |
---|---|---|

3 | 2 | 5.56% |

4 | 3 | 8.33% |

5 | 4 | 11.11% |

6 | 5 |
13.89% |

## When two dice are thrown the total outcomes are?

Note that there are **36 possibilities** for (a,b). This total number of possibilities can be obtained from the multiplication principle: there are 6 possibilities for a, and for each outcome for a, there are 6 possibilities for b. So, the total number of joint outcomes (a,b) is 6 times 6 which is 36.

## What is the probability of rolling a 5 or flipping heads?

Probability for tossing on heads=**0.5** Probability of rolling on odd number on die (1 or 3 or 5)=0.5 As per addition rule (A union B, A or B) that is 0.5+0.5=1 that seems impossible.

## What is the probability of rolling a 3 or getting heads?

The odds of getting heads are 1 : 1 (one to one, or even). b) Rolling a die and getting a 3. The sample space consists of 6 outcomes: 1 three and 5 not-three. The odds of getting three are **1 : 5 (one to five)**.

## How many outcomes would there be in the sample space for rolling 5 dice and flipping 2 coins?

If they can’t roll a six, there are 5 other numbers to roll, and either coin-flip is still allowed. So each person has 2×5=**10 possible outcomes**.

## What is the probability of rolling a 7 or 11 with two dice?

The probability of winning on the first roll is the probability of rolling 7 or 11, which is 1/6 plus 1/18, which equals to **2/9**. Suppose we roll 4 on the first roll (the probability of rolling 4 is 1/12). On each successive roll the probability of rolling 7 is 1/6 and the probability of rolling 4 is 1/12.

## What is the probability of rolling a 6 with 3 dice?

So, there are 125 out of 216 chances of a 6 NOT appearing when three dice are rolled. Simply subtract 125 from 216 which will give us the chances a 6 WILL appear when three dice are rolled, which is **91**. 91 out of 216 or 42.1 %.