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## What is the probability of getting a sum of 8 or higher in a single throw of two dice?

The required probability is **5/36** .

## What is the probability of getting a sum of 8 in rolling two dice?

Therefore theprobability that we get the sum as8 when two dice are thrown is **5/36**.

## What is the probability that the sum is 8 when throwing a dice given that the first die shows a 3?

The total number of ways to roll an 8 with 3 dice is therefore 21, and the probability of rolling an 8 is **21/216**, which is less than 5/36. heads out of 20 is (20 10 ) /220 ≈ 17.6%.

## What is the probability of getting a doublet of even number?

We know that the favourable outcomes are (2, 2), (4, 4), and (6, 6). So, the number of favourable outcomes is 3. We know that the number of possible outcomes is 36. Thus, the probability of getting a doublet of an even number is =**336=112**.

## What is the probability of getting 9 in a single throw of a dice?

= 4 / 36 = **1/9**.

## What is the probability of getting a total of 6 or 8 on a roll of a pair of dice?

Two (6-sided) dice roll probability table

Roll a… | Probability |
---|---|

6 | 15/36 (41.667%) |

7 | 21/36 (58.333%) |

8 | 26/36 (72.222%) |

9 | 30/36 (83.333%) |

## What is the probability of getting a sum of 7 when rolling two dice?

For each of the possible outcomes add the numbers on the two dice and count how many times this sum is 7. If you do so you will find that the sum is 7 for 6 of the possible outcomes. Thus the sum is a 7 in 6 of the 36 outcomes and hence the probability of rolling a 7 is **6/36 = 1/6**.

## What is the probability of getting a sum even numbers throwing a pair of dice?

5 Answers. Now, note that P(even|first was even)=P(second is even)=**1/2**. Similarly, P(even|first was odd)=P(second is odd)=1/2. Thus, we have P(even sum)=1/2(P(first was even)+P(first was odd))=1/2(1)=1/2.