# What is the probability of getting a sum 9 from the throws of a dice?

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## What is the probability of getting a sum 9 from three throws of a dice?

For each of the three throws, there is a 19 chance that you will get a sum of 9, while there is a 89 chance that you will get a sum that is not 9. For each throw (pair of 2 die), there can be 36 possible outcomes, so for three throws there can be 46656 possible outcomes.

## What is the probability of getting 9 in a single throw of die?

P(of getting a total of 9 or 11) = 1 / 6.

## What is the probability of getting a sum of 9 when two dice are thrown simultaneously?

probability 4/36 or 1/9. In order to get a sum of 9 with two dice, you would have to roll the pairs 4 & 5, 5 & 4, 3 & 6, or 6 & 3.

## What’s the probability of 9?

Probabilities for the two dice

Total Number of combinations Probability
6 5 13.89%
7 6 16.67%
8 5 13.89%
9 4 11.11%
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## What is the probability of obtaining 9 10 11 points with 3 dice?

Probability of a sum of 9: 25/216 = 11.6% Probability of a sum of 10: 27/216 = 12.5% Probability of a sum of 11: 27/216 = 12.5%

## What is the probability of getting 3 in a die?

Two (6-sided) dice roll probability table

Roll a… Probability
3 3/36 (8.333%)
4 6/36 (16.667%)
5 10/36 (27.778%)
6 15/36 (41.667%)

## What is the probability of getting a doublet of even number?

We know that the favourable outcomes are (2, 2), (4, 4), and (6, 6). So, the number of favourable outcomes is 3. We know that the number of possible outcomes is 36. Thus, the probability of getting a doublet of an even number is =336=112.

## What is the probability of getting a doublet when two dice are thrown?

Probability of getting a doublet = 6/36 = 1/6.

## What will be the probability of getting odd numbers if a dice is thrown?

Hence, the required probability of getting an odd number , P(E) = 1/2.

## What is the probability of getting at least one?

To find the probability of at least one of something, calculate the probability of none and then subtract that result from 1. That is, P(at least one) = 1 – P(none).